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The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list Asked 16 years, 4 months ago modified 2 years, 9 months ago viewed 285k times The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list.
Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like In python, how do i index a list with another list A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?
If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension
Please see how can i get a flat result from a list comprehension instead of a nested list? The most popular solutions here generally only flatten one level of the nested list See flatten an irregular (arbitrarily nested) list of lists for solutions that. Model status certified —models are expected to work with chromeos flex
Minor issues expected —models are likely to support at least basic functionality, but are still being worked on by our team You might run into minor issues In c# if i have a list of type bool What is the fastest way to determine if the list contains a true value
I don’t need to know how many or where the true value is
I just need to know if one e. A list of lists would essentially represent a tree structure, where each branch would constitute the same type as its parent, and its leaf nodes would represent values. Is the a short syntax for joining a list of lists into a single list ( or iterator) in python For example i have a list as follows and i want to iterate over a,b and c.
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